SIT1001 Probability and Statistics I Tutorial 5
Hello, dear friend, you can consult us at any time if you have any questions, add WeChat: daixieit
SIT1001 Probability and Statistics I
Tutorial 5
1. One characteristic of a car’s storage console that is checked by the manufacturer is the time in seconds that it takes for the lower storage compartment door to open completely. A random sample of size ��� = 5 yielded the following times:
1.1 0.9 1.4 1.1 1.0
a. Find the sample mean, ���̅.
b. Find the sample variance, ���2.
c. Find the sample standard deviation, ���.
[ 1.1 ; 0.0350 ; 0.1871 ]
2. The costs of 28 “300 level” textbooks (rounded to the nearest dollar) for spring 2004, selected from all major disciplines, were as follows:
128 |
23 |
108 |
104 |
44 |
77 |
25 |
112 |
45 |
65 |
116 |
53 |
19 |
84 |
20 |
115 |
93 |
55 |
80 |
73 |
108 |
98 |
18 |
58 |
75 |
45 |
19 |
25 |
a. Group these data into six classes using as class intervals (9.50, 29.50), (29.50, 49.50), and so on.
b. Construct a histogram and interpret the histogram.
c. Find the mean, ���̅ and locate it on your histogram.
d. Find the standard deviation, ���, and locate the points ���̅ ± ��� and ���̅ ± 2��� on your histogram.
[ a.Frequencies:(7,3,4,5,5,4) ; c.67.32 ; d.35.53 ]
3. Let ��� denote the concentration of ������������3 in milligrams per liter. Twenty observations of ��� are
130.8 |
129.9 |
131.5 |
131.2 |
129.5 |
132.7 |
131.5 |
127.8 |
133.7 |
132.2 |
134.8 |
131.7 |
133.9 |
129.8 |
131.4 |
128.8 |
132.7 |
132.8 |
131.4 |
131.3 |
a. Construct an ordered stem-and-leaf display, using stems of 127, 128, …, 134.
b. Find the midrange, range, interquartile range, median, sample mean and sample variance.
[ a. Frequency:(1,1,3,1,7,4,2,1), Depths:(1,2,5,6,(7),7,3,1) b. 131.3 , 7.0 , 2.575 , 131.45 , 131.47 , 3.034 ]
4. Let the random variable ��� have the p.d.f. ���(���) = 2(1 − ���), 0 ≤ ��� ≤ 1, zero elsewhere.
a. Sketch the graph of this p.d.f.
b. Determine and sketch the graph of the distribution function of ���.
c. Find
(i) ���(0 ≤ ��� ≤ 1⁄2)
(ii) ���(1⁄4 ≤ ��� ≤ 3⁄4)
(iii) ���(��� = 3⁄4) and (iv) ���(��� ≥ 3⁄4)
0, x < 0,
[ b. F(x) = {x(2 − x), 0 ≤ x < 1,
1, 1 ≤ x.
c. (i) 3/4, (ii) 1/2, (iii) 0, (iv) 1/16.]
5. For each of the following functions, (i) find the constant ��� so that ���(���) is a p.d.f. of a random variable ���, (ii) find the distribution function, ���(���) = ���(��� ≤ ���), and (iii) sketch graphs of the p.d.f. ���(���) and the distribution function ���(���).
a. ���(���) = 4������, 0 ≤ ��� ≤ 1,
b. ���(���) = ���√���, 0 ≤ ��� ≤ 4,
c. ���(���) = ���⁄���3⁄4 , 0 < ��� < 1.
[ a.(i) 3, (ii) F(x) = x4, 0 ≤ x ≤ 1;
b.(i) 3/16, (ii) F(x) = (1⁄8) x3⁄2, 0 ≤ x ≤ 4;
c.(i) 1/4, (ii) F(x) = x1/4, 0 ≤ x ≤ 1 ]
6. For each of the distributions in Question 5, find ���, ���2 and ���.
[ a. 4⁄5 , 2⁄75 , √6⁄15 ;
b. 12⁄5 , 192⁄175 , 8 √21⁄35 ;
c. 1⁄5 , 16⁄225 , 4⁄15 ]
7. The p.d.f. of ��� is ���(���) = ���⁄���3,
1 < ��� < ∞.
a. Calculate the value of ��� so that ���(���) is a p.d.f.
b. Find ���(���).
c. Show that ���������(���) is not finite.
[ a. ��� = 2 ; b. ���(���) = 2 ; c. ���(���2) is unbounded. ]
8. Let ���(���) = ln ���(���), where ���(���) is the moment-generating function of a random variable of the continuous type. Show that
a. ��� = ���′(0).
b. ���2 = ���′′(0).
9. The logistic distribution is associated with the distribution function
���(���) = (1 + ���−���)−1 , − ∞ < ��� < ∞.
Find the pdf of the logistic distribution and show that its graph is symmetric about
��� = 0.
[ ���(���) = ���−���
= ���−��� ���2��� = ������
= ���(−���) ]
(1+���−���)2
(1+���−���)2 ���2���
(������+1)2
10. The lifetime ��� (in years) of a machine has a p.d.f.
���(���) = 2��� ���−(���⁄���)2 , 0 < ��� < ∞.
���2
If ���(��� > 5) = 0.01, determine ���.
[ ��� = 2.33 ]
11. The life ��� in years of a voltage regulator of a car has the p.d.f.
���(���) =
3���2
73
���−(���⁄7)3
, 0 < ��� < ∞.
a. What is the probability that this regulator will last at least 7 years?
b. Given that it has lasted at least 7 years, what is the conditional probability it will last at least another 3.5 years?
[ a. 1⁄��� = 0.368 ; b. 1⁄���2.375 = 0.093 ]
12. Solve Question 2 using R.
2022-11-23